CBSE 11TH MATHEMATICS - Online Test
| p | q | ||||
| T | T | T | T | T | T |
| T | F | T | T | T | T |
| F | T | F | T | T | T |
| F | F | T | F | T | T |
Hence they are equivalent
Comparing the above equation with
focus is (0,-a)
putting x co-ordinate =0 we get x-4=0
=> x=4
and y co-ordinate =-a we get
=>y=4
hence (4,4) is the focus.
If ( 1 + tan ) ( 1 + tan ) = 2, then + =
represents
x=0 , y= , z= 0 which represent Y axisWe have 1600=
To form factors we have to do selections from a lot of 2's and 5's and multiply them together.
To form even factor we should choose at least one 2's from the lot , which will ensure that what ever be the remaining selection, their multiplication will always result in an even factor.
The number of ways to select atleast one ‘2’ from a lot of six identical ‘2’s will be 6 (i.e. select 1 or select 2 or select 3 or select 4 or select 5 or select 6)
And, we’ll select any number of ‘5 from a lot of two identical ‘5’s in 3 ways(select 0, select 1,select 2)
There fore the total number of selection of even factors=6x3=18
