CBSE 11TH MATHEMATICS - Online Test

Answer : Option A
Explaination / Solution:

We know that, 3median = mode + 2 mean

so, mean= (3 median - mode)/2      ........(1)

comparing equation(1) with the given equation

therefore, x=1/2

Answer : Option A
Explaination / Solution:

The lines are concurrent

On solving the lies 1 and 2 we get the point of intersection as (-1,2)

Similarly on solving lines 2 and 3,  the point of intersection is (-1,2)

Similarly solving the lines 3 and 4, the point of intersection is (-1,2)

on solving lines 1 and 4 the point of intersection is (-1,2)

Since the point of intersection is the same for all the lines, the lines are concurrent.

Answer : Option B
Explaination / Solution:

p: the figure is a rhombus  q: the diagonals  are perpendicular

Contrapositive of p→q is∼q→∼p

hence If the diagonals are not perpendicular, then the figure is not a rhombus

Answer : Option D
Explaination / Solution:

The given lines are paralle. Hence the tangents are parallel tangents. Distance between these lines is equal to the diameter

D = |8−(−7)|36+64√ = 3/2

Therefore the radius is 3/4

Answer : Option D
Explaination / Solution:

Answer : Option C
Explaination / Solution:

When n = 1 we have the value of the expression as 65 . Given that the expression is divisible be 64. Hence the value is -1.

Answer : Option A
Explaination / Solution:
No Explaination.

Answer : Option B
Explaination / Solution:

It can be square or rhombus(all sides are equal).Angle property must be mentioned.

Answer : Option C
Explaination / Solution:

The month of February  has either 28 days (non-Leap Year)  or 29 days(Leap Year).

Thus there are 2 possibility  for the number of days in February.

Also the first day of the month of February can be any of the 7 days in a week.

So total number of February calendars = 2 * 7 =14

Answer : Option D
Explaination / Solution: