CBSE 11TH MATHEMATICS - Online Test

Q1. If the two lines of regression are y = 3x – 5 and y = 2x – 4 , then ρ(X,Y) is equal to
Answer : Option A
Explaination / Solution:

let us assume that y = 3x – 5 and y = 2x – 4 are lines of regression of x on y and y on x respectively,therefore



but sign of ρ is same as  and 

therefore 


Q2. The lines ix + my + n = 0 , mx + ny + l = 0 and nx + ly +m = 0 are concurrent if
Answer : Option B
Explaination / Solution:

The required condition for concurrency is a3(b1c2 - b2c1) + b3(c1a2 - c2a1) + c3(a1b2 - a2b1) = 0

Here a1 = l, a=m, a3 = n and b1 = m, b2 = n, b3 = l and c1 = n, c2 = l and c3 = m

Substituting the values  we get

n(ml - n2) + l(nm - l2) +m(ln - m2) = 0

This implies l3 + m3 + n3 - 3lmn = 0

That is (l + m+ n)(l2 + m2 + n2 -lm -mn - nl) = 0

This implies l + m + n = 0


Q3. The contrapositive of the statement “ if  then I get first class” is
Answer : Option C
Explaination / Solution:

p:

q:I get first class

the contrapositive of . hence the answer is If I do not get a first class , then 


Q4. The line 3x – 4y = 0
Answer : Option A
Explaination / Solution:

After completing the square,we get


so center is (0,0) and radius is 5 units.

As the normal should pass through the centre of the circle, center should satisfy the equation of normal

so 3x – 4y = 0 is the equation of normal as (0,0) satisfy this equation.


Q5. The solution of tan 2 θ tan θ = 1 is
Answer : Option D
Explaination / Solution:



Q6. The sum of the terms in the nth bracket of the series 1 + (2+3+4) + (5+6+7+8+9) ….is
Answer : Option D
Explaination / Solution:

replace n = 1 we get the first term and n = 2 we get the sum of first two terms....

Q7. A dice is tossed once and even number has come up. The chance that it is either 2 or 4 is
Answer : Option D
Explaination / Solution:

Total number of ways of getting even number is 3

Out of these 3 even number we have to get either 2 or 4 which can be done in 2 ways.

So required probability is 2/3


Q8. The lines  intersect . The shortest distance between them is
Answer : Option C
Explaination / Solution:

Since the lines intersect.Hence they have a common point in them.hence the distance will be zero

Q9. The number of ways in which 8 different flowers can be strung to form a garland so that 4 particular flowers are never separated is
Answer : Option B
Explaination / Solution:

4 flowers which are always together can be considered as one SET, 

Therefore we have to arrange one SET ( 4 flowers ) and 4 other flowers into a garland. 

Which means, 5 things to be arranged in a garland. 

(5-1)! 

And the SET of flowers can arrange themselves within each other in 4! ways. 

Therefore 

(5-1)!*(4!) 

But, Garland, looked from front or behind does not matter. Therefore the clockwise and anti clockwise observation does not make difference. 

Therefore 

(5-1)! * (4!)/ 2 

= 288.

Q10. The value of  is
Answer : Option A
Explaination / Solution: