Using the formulae,
here
therefore
Area of the triangle formed by the coordiates( x1,y1), (x2,y2) and (x3,y3) is given by
[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
On solving the lines 1 and 2, the point of intersection is (0,0)
On solving the lines 2 and 3, the point of intersection is (4,8)
\On solving the line 3 and 1 , the point of intersection is (-2,-2)
Now substituting the values to find the area of the triangle,
Area = | [ 0 + 4(-2-0) +(-2)(0 - 8)] |
= 4 sq units
Solving the above two equations we get,
---(i)
---(ii)
Squaring both sides of (i) and (ii) and adding both the equation we get x2+y2=a2+b2.
which represents the locus of circle as
(i) it is quadratic equation
(ii) coeff of x2 = coeff of y2
(iiI) there is no trerm involving xy.


First we will fix one person from the 6 boys then 5 others can be arranged in 5! ways=120 ways
Now there are 6 places left in which 2 brothers can sit,so they can choose any 2 places from the 6 places in 6C2 ways=15 ways
Also 2 brothers can arrange themselves in 2! ways
So th ways in which the two brothers can be seated=15*2=30
Hence total ways in which all can be seated =120*30=3600
