Resolution
limit = 1.22 × λ / D
D
- diameter of pupil = 3 mm
λ
- wavelength = 500 nm
Resolution limit = distance between the dots / resolving diameter
=
1mm/d
[
1.22 × λ ] / D = 1mm / d
D
= [1mm × D ] / [ 1.22 × λ ] = [ 1
x 10-3 × 3 x 10-3 ] / [ 1.22 × 500 x10-9 ]
d = 4.918 ≈ 5m
Imax
= I1 + I2 + 2√(I1I2)
=
I + 4I + 2√(4I2)
=
I + 4I + 4I = 9I
Imin
= I1 + I2 - 2√(I1I2)
=
I + 4I − 2√(4I2)
=
I + 4I − 4I = I
d
= 5 × 10-5
cm = 5 × 10-7
m
λ=5320
Å = 5.32 × 10-7 m
For
visible region n=2
μ=?
One of the of Young’s double slits is covered with
a glass plate as shown in figure. The position of central maximum will,