Let P() be the point and Q (0,b,0) be any point on Y axis.
drs of PQ=(
drs of y axis (0,b,0)
Since PQ perpendicular to y axis.hence a1a2+b1b2+c1c2=0

hence the foot of perpendicular will be
To get the odd factors we will get rid of 2's
We will make the selection from only 3's and 5's
Number of ways 3 can be selected from a lot of two 3's= 3 ways ( one 3,two 3's or three 3's)
Number of ways 5 can be selected from a lot of two 5's= 3 ways ( one 5,two 5's or three 5's)
Therefore the number of odd factors is 3600= 3 X 3 =9
Now we can see for n=0,4,8....... the value of = 1
For n=1,5,9....... the value of =i
for n=2,6,10....... the value of =-1
for n=3,7,11....... the value of = -i
similarly for all negative integers also n takes any one value among 1 ,-1 , i ,-i


