TOTAL NO. OF OUTCOMES=62=36
no. of outcomes in which both throws same no.={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6
p(both throws same no.)=6/36=1/6
Since a student can solve every question in three ways- either he can attempt the first alternative , or the second alternative or he does not attemp that question
Hence the total ways in which a sudent can attempt one or more of 8 questions =
Therefore to find the number of all selections which a student can make for answering one or more questions ou tof 8 given questions = [ we will have to exclude only the case of not answering all the 8 questions]

which is not possible.
Hence we can say there is no solution for the system of equations
in any set having n elements then Total no of subsets=2n
so total subset = 25=32

