Total no. of outcomes = 6={2,2,2,6,6,6}
p(getting a six)=3/6=1/2
Given that there are 20 stations in the network .
Hence from each station 19 different tickets are possible
Therefore from 20 stations the number of different tickets possible=19 X 20=380



Hence the solution set is
which means
In this sequence the nth term is,
so, for n = 5,