CBSE 11TH MATHEMATICS - Online Test

p↔∼p   definition of p↔q≡(p→q)∧(q→p)

Hence F

Since the circle passes through (0,0) the equation reduces to 

c= 0 -----(1)

Since it passes through (1,0),

1 + 2g + c = 0

This implies g = -1/2

Since the circle touches the circle x2 + y2 = 9, their radii should be equal

2g2+f2+c−−−−−−−−−√ = 3

Substituting the values and simplifying we get f = ±2–√

Hence the centre is (1/2, −2–√)

We have a regular tetrahedron has 4 faces and we have to colour it with 4 different colours in 4!=24 ways.

But in this we will be getting many overcountings .

We have there are 12 ways in which we can orient a regular tetrahedron  

Hence the number of distinct ways of colouring a regular tetrahedron  with 4 different colours is 2412=2