If the lines are at right angles to each other, then the product of their slopes = -1. Slope of any line = -(coefficient of x/coeffiecient of y)
Therefore slope of line 1 = -(1/(k-1)
Slope of line 2 = -2/k2
Therefore X = - 1
That is k2 (k-1) = -2
i.e; k3 - k2 +2 = 0
On factorizing we get (k+1)(k2 -2k - 2) = 0
This imlpies k+1 is a factor, hence k = -1
Hence they are at right angles if k = -1
since T->F is false.
Hence q=F.
So p=T and q=F
If then is equal to
The direction ratio of the line joining ( x1 , y1 , z1 ) , and ( x2 , y2 , z2) = < x1-x2 , y1-y2 , z1-z2 >
The direction ratio of the line joining ( 1 , - 1 , 1 ) , and ( -1 , 1 , 1 ) = < 1+1 , -1-1 , 1-1> = < 2 , -2 , 0 >