= F
You have two different kinds of such three-digit even numbers.First is 5 at the hundred'splace and second 5 is not at the hundred'splace
In first case no is of the form 57x, where x is the unit's digit ,which can be 0,2,4,6,8 which is just 5 possibilities.Hence the no of possibilities in this case is 1x1x5=5
In second case the hundred's digit can be 1,2,3,,4,,6,7,8,or,9 which is 8 ways and the ten's digit can be any of the 9 numbers and unit digit can be any of the 5 even numbers .Therfore the no: of ways will be 8×9×5=360
So total we have 360 + 5 = 365 possibilities.