CBSE 11TH MATHEMATICS - Online Test
Q1. The Mode of the following items is 0,1,6,7,2,3,7,6,6,2,6,0,5,6,0.
Answer : Option B
Explaination / Solution:
6 is the most frequent value here.
Q2. The line passing through ( 1, 1 ) and parallel to the line 2x – 3y + 5 = 0 is
Answer : Option D
Explaination / Solution:
The required line is parallel to the given line, hence it has same slope
Therefore the equation of the required line is 2x-3y+k=0
Since it passes through (1,1)
2(1) - 3(1) +k = 0
Therefore k=1
Hence the equation of the required line is 2x - 3y + 1=0
Q3. If the inverse of implication p→q is defined as ∼p→∼q , then the inverse of proposition (p∧∼q)→r is
Answer : Option C
Explaination / Solution:
as given the rule of inverse in question it becomes ∼(p∧∼q)→∼r
=(∼p∨q)→∼r
Q4. The statement is true for all
Answer : Option C
Explaination / Solution:
Since if n = 1 we have 3>4, which is not true . If n = 2 then 9>8, which is true.
Q5. Which one of the following lines is farthest from the centre of the circle
Answer : Option D
Explaination / Solution:
after completing the square,we get
so center is (0,0) and equation of given line is 
by applying formula of distance of a point from a given line i.e., 
where(x1,y1) are the coordinates of point and A and B are coefficient of x,y in given line so d =
which is greatest.
by applying formula of distance of a point from a given line i.e., where(x1,y1) are the coordinates of point and A and B are coefficient of x,y in given line so d =
Q6. In a ΔABCΔABC , if a sin A = b sin B then the triangle is
Answer : Option C
Explaination / Solution:
Hence the triangle is isosceles.
Q7. The letters of the word ‘SOCIETY’ are arranged in such a manner that the vowels and consonants occur alternately, the number of different words so obtained is
Answer : Option B
Explaination / Solution:
there are four consonants and 3 vowels, therefore 3! * 4!
Q8. The distance of the point ( x , y , z ) from the XY –plane is
Answer : Option D
Explaination / Solution:
Let L be the foot of perpendicular segment from the point P (x,y,z) on XY plane
Now since L is the foot of perpendicular on XY plane so z coordinate will be zero so the point L will be (x,y,0)
then distance between these two will be = = |z|
Q9. If |z−2|=|z−6| then locus of z is given by :
Answer : Option D
Explaination / Solution:
We have any line of the form x=a constant is a line parallel to Y-axis.
Q10. If A ⊆B , then A∪B is equal to
Answer : Option D
Explaination / Solution:
A ⊆B refers to A set is contained in the Set B.So Set B is bigger.So union the sets will be B
