Civil Engineering - Online Test

Q1. The trigonometric Fourier series of an even function does not have the
Answer : Option C
Explaination / Solution:

For an even function Fourier series contains dc term and cosine term (even and odd harmonics).

Q2. The value of the integral where c is the circle |z| = 1 is given by
Answer : Option A
Explaination / Solution:

C R Integrals is  where C is circle |z| = 1
So poles are outside the unit circle. 

Q3. Let , and h(t)  is a filter matched to g(t). if g(t) is applied as input to h(t) then the Fourier transform of the output is
Answer : Option D
Explaination / Solution:

The matched filter is characterized by a frequency response that is given as


Q4. Let U and V be two independent zero mean Gaussain random variables of variances 1/4 and 1/9 respectively. The probability

Answer : Option B
Explaination / Solution:

Given, random variables U and V with mean zero and variances 1/4 and 1/9

The distribution is shown in the figure below

We can express the distribution in standard form by assuming


Q5. If   then the initial and final values of f(t) are respectively
Answer : Option B
Explaination / Solution:
No Explaination.


Q6. A numerical solution of the equation  can be obtained using Newton- Raphson method. If the starting value is x = 2 for the iteration, the value of x that is to be used in the next step is
Answer : Option C
Explaination / Solution:


Substituting x0 = 2 we get

Newton Raphson Method

Substituting all values we have


Q7. The system of equations x + Y + z = 6 x + 4y + 6y = 20 x + 4y + λz = μ has NO solution for values of λ and μ given by
Answer : Option B
Explaination / Solution:

Writing A:B we have

Apply R3R3 – R2

For equation to have solution, rank of A and A:B must be same. Thus for no solution; λ = 6, μ ≠ 20


Q8. A fair dice is tossed two times. The probability that the second toss results in a value that is higher than the first toss is
Answer : Option C
Explaination / Solution:

Total outcome are 36 out of which favorable outcomes are : (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 3), (2, 4), (2, 5), (2, 6); (3, 4), (3, 5), (3, 6), (4, 5), (4, 6), (5, 6) which are 15. P(E) = (No of favourable outcomes/No of total outcomes) = 15/36 = 5/12

Q9. Three friends, R, S and T shared toffee from a bowl. R took 1/3rd of the toffees, but returned four to the bowl. S took 1/4th of what was left but returned three toffees to the bowl. T took half of the remainder but returned two back into the bowl. If the bowl had 17 toffees left, how many toffees-were originally there in the bowl?
Answer : Option C
Explaination / Solution:

Let total no of toffees be x . The following table shows the all calculations.



Q10. Given that   and q is any non-zero real number, the value of |f(q) - f(-q)| is
Answer : Option D
Explaination / Solution: