Answer : Option BExplaination / Solution:
This function exists only if
cosx−1≥0
⇒cosx≥1
⇒cosx>1
OR
cosx=1
since maximum value of cosine function is 1 so, cos x >1 is not possible
so,
cosx=1
cosx=cos2nπ
⇒x=2nπ(n∈I)
Q2.If R is a relation from a non – empty set A to a non – empty set B, then
Answer : Option CExplaination / Solution:
Let A and B be two sets . Then a relation R from set A to set B is a subset of A×B.Thus , R is a relation from A to B ⇔R⊆A×B⇔R⊆A×B.
Q4.Let R be the relation on N defined as x R y if x + 2 y = 8. The domain of R is
Answer : Option AExplaination / Solution:
As x R y if x + 2 y = 8 , therefore , domain of the relation R is given by x = 8 – 2y∈N. When y = 1, ⇒x = 6 ,when y = 2, ⇒x =4 , when y =3 , ⇒x = 2 . therefore domain is { 2, 4, 6 }.
Q5.Which of the following is not an equivalence relation on I, the set of integers ; x, y
Answer : Option BExplaination / Solution:
f R is a relation defined by xRy:ifx⩽y, then R is reflexive and transitive .But , it is not symmetric. Hence , R is not an equivalence relation.
Q6.Let A = {a, b, c} and R = {(a, a), (b, b), (c, c), (b, c) } be a relation on A. Here, R is
Answer : Option DExplaination / Solution:
Any relation R is reflexive if x R x for all x ∈ R. Here ,(a, a), (b, b), (c, c)∈ R. Therefore , R is reflexive.
Q7.R = {(1, 1), (2, 2), (1, 2), (2, 1), (2, 3)} be a relation on A, then R is
Answer : Option BExplaination / Solution: A relation R on a non empty set A is said to be reflexive if xRx for all x ∈R , Therefore , R is not reflexive. A relation R on a non empty set A is said to be symmetric if xRy⇔yRx, for all x , y ∈R Therefore, R is not symmetric. A relation R on a non empty set A is said to be antisymmetric if xRy and yRx⇒x = y , for all x , y ∈R.Therefore, R is not antisymmetric.
Q8.Let A = {1, 2, 3}. Which of the following is not an equivalence relation on A ?
Answer : Option AExplaination / Solution: A relation R on a non empty set A is said to be reflexive iff xRx for all x ∈ R . A relation R on a non empty set A is said to be symmetric iff xRy⇔yRx, for all x , y ∈R . A relation R on a non empty set A is said to be transitive iff xRy and yRz⇒xRz, for all x ∈ R. An equivalence relation satisfies all these three properties. . None of the given relations satisfies all three properties of equivalence relation.
Q9.Let A = {1, 2, 3}, then the relation R = {(1, 1), (2, 2), (1, 3)} on A is
Answer : Option CExplaination / Solution:
The given relation is not reflexive , as (3,3)∉R, The given relation is not symmetric , as (1,3)∈ R , but (3,1) ∉R, , The given relation is transitive as (1,1) )∈ R and (1,3) )∈R.
Q10.Let A = {1, 2, 3}, then the relation R = {(1, 1), (1, 2), (2, 1)} on A is
Answer : Option CExplaination / Solution:
A relation R on a non empty set A is said to be symmetric iff xRy⇔yRx, for all x , y ∈R Clearly , (1, 2), and (2, 1) both lies in R. Therefore ,R is symmetric.
Total Question/Mark :
Scored Mark :
Mark for Correct Answer : 1
Mark for Wrong Answer : -0.5
Mark for Left Answer : 0