Q1.cyclotron frequency of a charged particle having charge q and mass m in a cyclotron producing magnetic field B is
Answer : Option BExplaination / Solution: A particle of charge q moving with a speed v on entering a magnetic field B, experiences magnetic Lorentz force which acts as a centripetal force.
Q2.what is common to both biot savart law and ampere's law
Answer : Option DExplaination / Solution: Both Biot- Savart’s lawdB⃗ =μ04πIdl⃗ ×r^r2and ampere’s circuital law∮B⃗ ⋅dl⃗ =μ0Ideal with the consequences of steady current. Ampere’s circuital law is to Biot- savart’s law as is Gauss’s law to Coulomb’s law in electrostatics.
Answer : Option AExplaination / Solution: the expression for Ampere’s circuital law is ∮B⃗ ⋅dl⃗ =μ0Iwhere I is the current included in the surface bounded by the line integral.
Q4.The magnetic field at the center of a solenoid coil having n turns and carrying a current I in air is
Answer : Option BExplaination / Solution: The magnetic field at the centre of a solenoid with air core is B=μ0nI.where,μ0is the permeability of free space, n the number of turns per unit length and I is the current flowing through the solenoid.
Q5.The magnetic field at the center of a toroidal coil having n turns,radius r and carrying a current I in air is
Answer : Option BExplaination / Solution: A toroid is a solenoid wound on itself. The magnetic field exists only in the region of the hollow circular ring which has the turns of wire wound on it. Using Ampere’s circuital law,B(2πr)=μ0NI;B=μ0NI2πr
Q6.For two parallel wires carrying currents Ia and Ib seperated by a distance d, the magnitude of force acting on length L of any of the wires is
Answer : Option BExplaination / Solution: The conductor carrying current Ib is placed in the magnetic field B=μ0Ia2πdcreated by the conductor carrying current Ia. The force it experiencesF=BIbl=μ0IaIbl2πd
Q7.A rectangular current-carrying coil having n turns,area A and a current I flowing, in a uniform magnetic field B experiences a maximum ,torque equal to
Answer : Option AExplaination / Solution: The torque experienced by a current carrying conductor placed in a magnetic field is given by τ=NBIAsinθ.This has a maximum value whensinθ=1;sinθ=1
Q8.magnetic moment of a single-turn current loop of aluminium wire of area A,carrying a current I in a wire of diameter d is
Answer : Option BExplaination / Solution: The torque experienced by a current carrying coil of N turns placed in a magnetic fieldτ⃗ =NIA⃗ ×B⃗ .For N =1,τ⃗ =IA⃗ ×B⃗ Comparing with torque experienced by a electric dipole
Q9.magnitude of the magnetic moment of an electron of mass me if e is the charge on the electron and angular momentum is l, is
Answer : Option AExplaination / Solution: The electron moving in a circular orbit of radius r with a speed v and time period T constitutes a current i=eT.sinceT=2πrv,thereforei=ev2πrThe orbital magnetic moment of the electron μl=iA=ev2πr×πr2=evr2The angular momentum of the electronl=mevr ,sincevr=lmetherefore,μl=e2mel
Q10.In a moving coil galvanometer the current through the coil produces a torque to turn the coil. The torque is balanced by
Answer : Option BExplaination / Solution:
In a moving coil galvanometer, the coil is pivoted on a helical spring. When current passes through the coil, it experiences a torque and deflects. A restoring torque is set up in the helical spring which tries to restore the coil to its original position.
Total Question/Mark :
Scored Mark :
Mark for Correct Answer : 1
Mark for Wrong Answer : -0.5
Mark for Left Answer : 0