Q1.One mole of an ideal monatomic gas is at an initial temperature of 300 K. The gas undergoes an isovolumetric process, acquiring 500 J of energy by heat. It then undergoes an isobaric process, losing this same amount of energy by heat. Determine the new temperature of the gas
Answer : Option AExplaination / Solution:
for monoatomic gas CV = 1.5R, CP = 2.5R
At const volume,
Q = 500 J
Q=nCVΔT500=1×1.5×8.31(T1−300)T1=340K
At const pressure Q = 500 J
Q=nCPΔT500=1×2.5×8.31(340−T2)T2=316K
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