Basic Numeracy - Online Test

Speed=		60 x	5	m/sec	=		50	m/sec.
			18				3

Length of the train = (Speed x Time).

Length of the train =		50	x 9	m = 150 m.
		3

Speed of the train relative to man =		125	m/sec
		10

=		25	m/sec.
		2

=		25	x	18	km/hr
		2		5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

 x - 5 = 45          x = 50 km/hr.

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100 m, ACB = 30° and ADB = 45°.

AB	= tan 30° =	1	AC = AB x √3 = 100√3 m.
AC		√3

AB	= tan 45° = 1          AD = AB = 100 m.
AD

CD = (AC + AD)	= (100√3 + 100) m
	= 100(√3 + 1)
	= (100 x 2.73) m
	= 273 m.

Let AB be the wall and BC be the ladder.

Then, ACB = 60º and AC = 4.6 m.

BC	= 2 x AC
	= (2 x 4.6) m
	= 9.2 m.

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for 3 years = Rs.(39 x 3) = Rs. 117.

 Principal = Rs. (815 - 117) = Rs. 698.

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then,		x x 14 x 2		+		(13900 - x) x 11 x 2		= 3508
		100				100

 28x - 22x = 350800 - (13900 x 22)

 6x = 45000

 x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

		20 - x	x 100 = 25
		x

 2000 - 100x = 25x

125x = 2000

 x = 16.

Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs. 420.

Profit = Rs. (420 - 125) = Rs. 295.

Required percentage =		295	x 100	%	=	1475	% = 70% (approximately).
		420				21

Let their marks be (x + 9) and x.

 25(x + 9) = 14(2x + 9)

 3x = 99

 x = 33

So, their marks are 42 and 33.

Suppose originally he had x apples.

Then, (100 - 40)% of x = 420.

	60	x x = 420
	100

x =		420 x 100	= 700.
		60