Speed= | 60 x | 5 | m/sec | = | 50 | m/sec. | ||

18 | 3 |

Length of the train = (Speed x Time).

Length of the train = | 50 | x 9 | m = 150 m. | |

3 |

Speed of the train relative to man = | 125 | m/sec | |

10 |

= | 25 | m/sec. | |

2 |

= | 25 | x | 18 | km/hr | |

2 | 5 |

= 45 km/hr.

Let the speed of the train be *x* km/hr. Then, relative speed = (*x* - 5) km/hr.

*x* - 5 = 45 *x* = 50 km/hr.

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100 m, ACB = 30° and ADB = 45°.

AB | = tan 30° = | 1 | AC = AB x √3 = 100√3 m. |

AC | √3 |

AB | = tan 45° = 1 AD = AB = 100 m. |

AD |

CD = (AC + AD) | = (100√3 + 100) m |

= 100(√3 + 1) | |

= (100 x 2.73) m | |

= 273 m. |

Let AB be the wall and BC be the ladder.

Then, ACB = 60º and AC = 4.6 m.

AC | = cos 60º = | 1 |

BC | 2 |

BC | = 2 x AC |

= (2 x 4.6) m | |

= 9.2 m. |

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for 3 years = Rs.(39 x 3) = Rs. 117.

Principal = Rs. (815 - 117) = Rs. 698.

Let the sum invested in Scheme A be Rs. *x* and that in Scheme B be Rs. (13900 - *x*).

Then, | x x 14 x 2 | + | (13900 - x) x 11 x 2 | = 3508 | ||||

100 | 100 |

28*x* - 22*x* = 350800 - (13900 x 22)

6*x* = 45000

*x* = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Let C.P. of each article be Re. 1 C.P. of *x* articles = Rs. *x*.

S.P. of *x* articles = Rs. 20.

Profit = Rs. (20 - *x*).

20 - x | x 100 = 25 | |||

x |

2000 - 100*x* = 25*x*

125*x* = 2000

*x* = 16.

Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs. 420.

Profit = Rs. (420 - 125) = Rs. 295.

Required percentage = | 295 | x 100 | % | = | 1475 | % = 70% (approximately). | |

420 | 21 |

Let their marks be (*x* + 9) and *x*.

Then, x + 9 = | 56 | (x + 9 + x) |

100 |

25(*x* + 9) = 14(2*x* + 9)

3*x* = 99

*x* = 33

So, their marks are 42 and 33.

Suppose originally he had *x* apples.

Then, (100 - 40)% of *x* = 420.

60 | x x = 420 | |

100 |

x = | 420 x 100 | = 700. | |

60 |