Speed= | ![]() | 60 x | 5 | ![]() | = | ![]() | 50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() | ![]() | 50 | x 9 | ![]() |
3 |
Speed of the train relative to man = | ![]() | 125 | ![]() |
10 |
= | ![]() | 25 | ![]() |
2 |
= | ![]() | 25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, ACB = 30° and
ADB = 45°.
AB | = tan 30° = | 1 | ![]() |
AC | √3 |
AB | = tan 45° = 1 ![]() |
AD |
![]() | = (100√3 + 100) m |
= 100(√3 + 1) | |
= (100 x 2.73) m | |
= 273 m. |
Let AB be the wall and BC be the ladder.
Then, ACB = 60º and AC = 4.6 m.
AC | = cos 60º = | 1 |
BC | 2 |
![]() | = 2 x AC |
= (2 x 4.6) m | |
= 9.2 m. |
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then, | ![]() | x x 14 x 2 | ![]() | + | ![]() | (13900 - x) x 11 x 2 | ![]() | = 3508 |
100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
![]() | ![]() | 20 - x | x 100 = 25 | ![]() |
x |
2000 - 100x = 25x
125x = 2000
x = 16.
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
![]() | ![]() | 295 | x 100 | ![]() | = | 1475 | % = 70% (approximately). |
420 | 21 |
Let their marks be (x + 9) and x.
Then, x + 9 = | 56 | (x + 9 + x) |
100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Suppose originally he had x apples.
Then, (100 - 40)% of x = 420.
![]() | 60 | x x = 420 |
100 |
![]() | ![]() | 420 x 100 | ![]() |
60 |