Forming a differential equation representing the given family of curves by eliminating arbitrary constants a and b from yields the differential equation
Let number of units of food F1 = x
And number of units of food F2 = y
Therefore , the above L.P.P. is given as :
Minimise , Z = 4x +6y , subject to the constraints : 3 x + 6y ≥ 80, 4x + 3y ≥ 100, x,y ≥ 0.,
Corner points | Z =4x +6 y |
B(80/3 , 0 ) | 320/3 |
D(24,4/3 ) | 104…………………(Min.) |
A(0,100/3) | 200 |
Corner points Z =4x +6 y B(80/3 , 0 ) 320/3 D(24,4/3 ) 104…………………(Min.) A(0,100/3) 200 Here Z = 104 is minimum. i.e. Minimum cost = Rs 104.