Let number of packages of screws A produced = x
And number of packages of screws B produced = y
Therefore , the above L.P.P. is given as :
Maximise , Z = 7x +10y , subject to the constraints : 4x +6y ≤ 240 and. 6x +3y ≤ 240 i.e. 2x +3y ≤ 120 and 2x +y ≤ 80 , x, y ≥ 0.
Corner points | Z =7 x +10 y |
O( 0 , 0 ) | 0 |
D(40,0 ) | 280 |
A(0,40) | 400 |
B(30,20) | 410…………………(Max.) |
Here Z = 410 is maximum.
i.e 30 packages of screws A and 20 packages of screws B; Maximum profit = Rs 410.