CBSE 12TH MATHEMATICS - Online Test

Answer : Option D
Explaination / Solution:

f′(x)=1+sinx⩾0∀x∈R.
(∵−1⩽sinx⩽1,∴0⩽1+sinx⩽2)

Hence an increasing function.

Answer : Option A
Explaination / Solution:

expanding along R1

1(cos2x−sin2x)=cos2x.

Answer : Option C
Explaination / Solution:

In Corner point method for solving a linear programming problem one finds the feasible region of the linear programming problem ,determines its corner points and evaluates the objective function Z = ax + by at each corner point. Let M and m respectively be the largest and smallest values at corner points. In case feasible region is unbounded, M is the maximum value of the objective function if the open half plane determined by ax + by > M has no point in common with the feasible region . Otherwise Z has no maximum value.

Answer : Option B
Explaination / Solution:

Since the range is represented by the y- co ordinate of the ordered pair ( x , y ).Therefore, range of the given relation is { b , c }.

Answer : Option A
Explaination / Solution:

Answer : Option C
Explaination / Solution:

If a vector is multiplied by any scalar then , the result is always a vector.

Answer : Option D
Explaination / Solution:

Two events A and B will be independent, then 

Answer : Option B
Explaination / Solution:

Answer : Option B
Explaination / Solution:

sin2650−cos2650= −cos50+sin50
between 0 to 900 cosθ>sinθ$cos\theta >sin\theta$  there fore answer is negative

Answer : Option D
Explaination / Solution:

limx→a(x−a)sin1(x−a)$\frac{)}{}$ =limh→0hsin1h=0=f(a)