
Let the consecutive even positive integers be x and x+2.
By data, x>5 and
Now
So we have the least possible value of x is 6 and the maximum value of x is 10.
Therefore the possible pairs of consecutive even positive integers are (6,8) ,(8,10) ,(10,12).

Equation of the line which perpendicular to the given line is x - y + k = 0
Since this line passes through (2,-3)
2-(-3) + k = 0
This implies k= -5
Hence the equation og the line is x - y =5
On solving the lines x+y=0 and x-y=5, we get the point of intersection as x = 5/2 and y = -5/2
Hence (5/2,-5/2) is the coordinates of orthogonal projection.
Given centre = (1,2)
Therefore radius = = 5 units
Area of the circle is = sq units
