If the coefficients of 2nd ,3rd and 4th terms in the expansion of are in A.P. then

N is set of natural number,so
x = 1/y
when y=1 then x=1
so
1 Q


The equation of the pair of straight lines paasing through the origin is fiven by is given by ax2 + 2hxy + by2 =0
The condition for perpendicularity between the pair of lines is a+b = 0
Hence the locus of the pair of these perpendicular straight lines should be xy = 0
Because line joining the points (a, 0) and (0, b) will be diameter and it's mid-point will be centre of the circle.
Or let the equation of circle be
as circle passes through (0,0) , (a,0) and (0,b), they will satisfy the above equation
putting the points in above equation we get
---(ii)
---(iii)
Solving (i) and (ii),we get h=
whereas solving (i) and (iii) we get k=
hence its center is
he value of lies between - 1 and 1
But when t=2 the value of is which is more than 1 , so it is not possible.