Let the oxidation number of P be x. As we already know oxidation number of other atoms so we can calculate that of P too.
Na = +1
H= +1 (+2 for hydrogen molecule)
O = -2
Now calculating oxidation number of P:-
1 +2 + x +(-8) = 0
On solving we get x= +5.
Consider the chemical equation ,
----- KOH + ----- H3PO4 → ----- K3PO4 + ----- H2O.
The equation can be balanced by inserting the following in blank spaces
The given equation gets balanced by inserting the coefficients (3 , 1 ,1 ,3 ) in blank spaces from LHS to RHS . Thus, the balanced equation for the given reacion is ,
3KOH + H3PO4 → K3PO4 + 3H2O.
= -RTln K
where is standard Gibbs energy change, K is equilibrium constant, R is universal gas constant and T is temperature in kelvin scale