Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If two stones are picked at random, what is the probability that both are blue?

Probability if both is blue

Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If four balls are picked at random, what is the probability that two are blue and two are red?

Probability if two are Blue and two are Red

[(^{4}C_{2}*^{5}C_{2})/^{12}C_{4}] = (6*10)/495 → 4/33

Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If three balls are picked at random, what is the probability that at least one is green?

Probability if at least one is Green

[1-(^{9}C_{3}/^{12}C_{3})] = 84/220 → 34/55

Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If two balls are picked at random, what is the probability that either both are red or both are blue?

Probabilities if both either are Red or either are blue

= (^{5}C_{2} + ^{4}C_{2})/^{12}C_{2} = (10+6)/66 → 8/33

Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If four balls are picked at random, what is the probability that two are blue, one is green and one is red?

Probabilities if two are blue and one is green and one is red

= [(^{4}C_{2}*^{3}C_{1}*^{5}C_{1})/ ^{12}C_{4}] = (6*3*5)/(495) = 2/11

Direction: Study the given information carefully and answer the questions that follow—

A store contains 4 red, 5 blue, 4 green shirts.

If two shirts are picked at random, what is the probability that both are green?

Probabilities if both are green

Probability if two are Blue and one are Red

[(^{5}C_{2}*^{4}C_{1})/^{13}C_{3}] = (10*4)/286 → 20/143

Probability if at least one is Green

[1-(^{9}C_{2}/^{13}C_{2})] = 42/78 → 7/13

Probabilities if both either are Red or either are green

(^{4}C_{2} + ^{4}C_{2})/^{13}C_{2} = (6+6)/78 → 2/13

Probabilities if at most one is blue =

[(^{5}C_{0}*^{8}C_{2}+ ^{5}C_{1}*^{8}C_{1})/ ^{13}C_{2}] = (1*28 + 5*8)/(78) = 34/39