Data Interpretation - Online Test
Q1. 
Directions: Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different years
What was the total number of failed candidates from school-C in the year 2008 and the number of candidates who appeared in the exam from school-D in the year 2006?
Answer : Option E
Explaination / Solution:
Number of Failed candidates from school-C in the year 2008 = 96
Number of appeared candidates from school-D in the year 2006 = 235
Required number
= 96 + 235
= 331
Q2.
Directions: Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different years
In which year was the difference between the number of candidates who appeared and passed in the exam from school-B second lowest?
Answer : Option B
Explaination / Solution:
Year 2005 is the second lowest.
Q3.
Directions: Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different years
What was the respective ratio between the number of candidates who appeared from school-C in the year 2006 and the number of candidate who passed in the exam from school-D in the year 2009?
Answer : Option A
Explaination / Solution:
Number of appeared candidates from school-C in the year 2006 = 693
Number of passed candidates from school-D in the year 2009 = 252
Required Ratio
= 693 : 252
= 11 : 4
Q4.
Directions: Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different years
Number of candidates who passed in the exam from school B in the year 2005 was approximately what percent of number of candidates who appeared from school-A in the year 2008?
Answer : Option E
Explaination / Solution:
Number of passed candidates from school B in the year 2005 = 435
Number of appeared candidates from school-A in the year 2008 = 546
Required percentage
= (435/546)*100
= 80 (approx)
Q5.
Directions: Study the table carefully to answer the questions that follow:
Candidates who appeared and passed in the test from four schools in six different years
What was the approximate percent increase in the number of candidates who passed in the exam from school-A in the year 2009 as compared to the previous year?
Answer : Option C
Explaination / Solution:
Number of passed candidates from school A in the year 2008 = 346
Number of passed candidates from school A in the year 2009 = 435
Percentage Increase = (89/346)*100
= 26 (approx)
Q6.
Direction: Study the pie charts carefully to answer the questions that follow:
Percent wise distribution of players and female players who play five different sports total number of players 6200 out of which number of female players is 3200.
What is the Total number of players both male and female who play cricket and rugby ?
Answer : Option D
Explaination / Solution:
Total no of players who play cricket & rugby together = 34% of 6200 + 15% of 6200
Total players = 2108 + 930 = 3038
Short Tricks:-
Add the percentage values of both game then calculate the values.
49% of 6200 = 3038
Q7.
Direction: Study the pie charts carefully to answer the questions that follow:
Percent wise distribution of players and female players who play five different sports total number of players 6200 out of which number of female players is 3200.
What is the difference between the number of the female players who play lawn tennis and the number of male players who play Rugby?
Answer : Option C
Explaination / Solution:
No of Female players who play lawn tennis = (3200*22)/100 = 704
No of male players who play rugby = [(6200*15)/100]-[(3200*10)/100]
= 930 – 320 = 610
Required difference = 704 – 610 = 94
Q8.
Direction: Study the pie charts carefully to answer the questions that follow:
Percent wise distribution of players and female players who play five different sports total number of players 6200 out of which number of female players is 3200.
What is the respective ratio of the number of female players who play cricket and number of female players who play Hockey?
Answer : Option C
Explaination / Solution:
Number of female player who play cricket = (3200*40)/100 = 1280
Number of female player who play hockey = (3200*15)/100 = 480
Ratio = 1280:480 = 8:3
Short Tricks:-
These type of the question solve by only percentage values not need to calculate number of player because total number of player same in both case.
40:15 ---> 8:3
Q9.
Direction: Study the pie charts carefully to answer the questions that follow:
Percent wise distribution of players and female players who play five different sports total number of players 6200 out of which number of female players is 3200.
What is the total number of male players who play football?
Answer : Option D
Explaination / Solution:
No of male players who play football = [(6200*17)/100]-[(3200*13)/100]
1054 - 416 = 638
Q10.
Direction: Study the pie charts carefully to answer the questions that follow:
Percent wise distribution of players and female players who play five different sports total number of players 6200 out of which number of female players is 3200.
Number of male players who play rugby is approximately, what per cent of the total number of players who play lawn tennis?
Answer : Option A
Explaination / Solution:
No of male players who play rugby = [(6200*15)/100]-[(3200*10)/100 = 610
No of players who play lawn tennis
= (6200*22)/100 = 1364
Required% = (610/1364)*100 = 45%
