Measures of Central Tendency - Online Test
Q1. On his first 5 biology tests, Bob received the following scores: 72, 86, 92, 63, and 77. What test score must Bob earn on his sixth test so that his average (mean score) for all six tests will be 80
Answer : Option A
Explaination / Solution:
N= 5 , Values of all observations = 72+86+92+63+77= 390 i.e. 90 (6 x 80) number less all the observations of Bob’s score.
Bob need to score in 6th Test = 90
So that his Sum of the values of all 6 test =480
Bob need to score in 6th Test = 90
So that his Sum of the values of all 6 test =480
Q2. If the values of mean and median are 40 and 48. Find out the most probable value of mode.
Answer : Option D
Explaination / Solution:
When the frequencies are not properly distributed it is called as an asymmetrical or skewed distribution. If it is moderately asymmetrical distribution the following empirical relationship holds good given by Karl Pearson and is expressed as: Mode = 3 Median - 2 Mean. 144 - 80 = 64
