That is C1 and C2 are identical
so value of determinant =0
hence area of triangle =0

Since, we know that
pre multiply by A,
(since AA-1=)


Let A be a non singular square matrix of order n then
det(adjA)=|A|n-1
here order is 3 so det(adj A)=|A|3-1=|A|2


lies in the interval