GENERAL APTITUDE - Online Test
xz = y2 
10(0.48z) = 10(2 x 0.70) = 101.40
0.48z = 1.40
| z = | 140 | = | 35 | = 2.9 (approx.) |
| 48 | 12 |
| 72519 x 9999 | = 72519 x (10000 - 1) |
| = 72519 x 10000 - 72519 x 1 | |
| = 725190000 - 72519 | |
| = 725117481. |
Following are the conditions for selecting an IT officer in an organization.
The candidate must –
(i) be a BE/BTech in IT or Computer Science with at least 60% marks.
(ii) be at least 20 years and not more than 26 years as on 01-11-2016.
(iii) have secured at least 60% marks in written test
(iv) have secured at least 40% marks in interview
In the case of candidate who fulfills all conditions except –
(a) At (ii) above, but is a post graduate, his case to be referred as GM.
(b) at (iv) above, but has secured at least 35% marks in interview and at least 70% marks in written test, his case to be referred as VP.
In each question below, details of a candidate are provided followed by a question and 5 courses of action. Select the course of action that applies to the person’s candidature.
Medha completed her BTech in IT in the year 2012. Which condition/s below will lead to her selecting as the IT officer?
(i) She secured 65% marks in written test.
(ii) She was born on 4th November 1990.
(iii) She secured 50% marks in interview.
