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ce gate 2010
TEST : 7
Engineering Mathematics
Prepare / Learn
Q1.
The solution to the ordinary differential equation
is
A.
y = c
1
e
3x
+ c
2
e
-2x
B.
y = c
1
e
3x
+ c
2
e
2x
C.
y = c
1
e
-3x
+ c
2
e
2x
D.
y = c
1
e
-3x
+ c
2
e
-2x
View Solution
Add Work Space
Answer :
Option C
Explaination / Solution:
No Explaination.
Engineering Mathematics
Prepare / Learn
Q2.
The inverse of the matrix
is
A.
B.
C.
D.
View Solution
Add Work Space
Answer :
Option B
Explaination / Solution:
No Explaination.
Engineering Mathematics
Prepare / Learn
Q3.
The table below gives values of a function F(x) obtained for values of x at intervals of 0.25.
The value of the integral of the function between the limits 0 to 1 using Simpson’s rule is
A.
0.7854
B.
2.3562
C.
3.1416
D.
7.5000
View Solution
Add Work Space
Answer :
Option A
Explaination / Solution:
No Explaination.
Engineering Mathematics
Prepare / Learn
Q4.
The partial differential equation that can be formed from z = ax + by + ab has the form
A.
z = px + qy
B.
z = px + pq
C.
z = px + qy + pq
D.
z = qx + pq
View Solution
Add Work Space
Answer :
Option C
Explaination / Solution:
No Explaination.
Engineering Mathematics
Prepare / Learn
Q5.
Given a function f(x,y) = 4x
2
+ 6y
2
- 8x - 4y + 8. The optimal value of f(x,y)
A.
is a minimum equal to 10/3
B.
is a maximum equal to 10/3
C.
is a minimum equal to 8/3
D.
is a maximum equal to 8/3
View Solution
Add Work Space
Answer :
Option A
Explaination / Solution:
No Explaination.
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ce gate 2010
TEST : 7
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