CBSE 12TH MATHEMATICS - Online Test
Q1. Variable separation method can be used to solveFirst Order, First Degree Differential Equations in which y’ is of the form.
Answer : Option B
Explaination / Solution:
y’ = h(x)g(y) since we can segregate functions of y with dy and x with dx.
Q2.
Find the approximate value of f(2.01) where
Answer : Option B
Explaination / Solution:
Q3. Determine the maximum value of Z = 3x + 4y if the feasible region (shaded) for a LPP is shown in Figure above.
Answer : Option B
Explaination / Solution:
Here , maximize Z = 3x+4y ,
Corner points | Z = 3x + 4 y |
C( 0 ,38 ) | 132 |
B ( 52 ,0) | 156 |
D(44 , 16) | 196 ………………….(Max.) |
Hence the maximum value is 196
Q4. The domain of the function
Answer : Option C
Explaination / Solution:
The domain of the function f(x) is all reals,because f(x) is defined for all real values of x.
Q5. The roots of the equation 
Answer : Option C
Explaination / Solution:
Q6. The area bounded by the curves y = equal to
Answer : Option B
Explaination / Solution:
Q7.
If is the angle between two vectors 
then 
only when
Answer : Option D
Explaination / Solution:
Q8. is equal to
Answer : Option C
Explaination / Solution:
=2–√∫0πsinx2dx=2–√[−cosx212]π0=−22–√[cosπ2−cos0]=22.−−√
Q9. The solution of the equation is given by
Answer : Option A
Explaination / Solution:
x= -1/2 does not satisfy the given equation.
Q10. If is the identity matrix of order n, the
Answer : Option C
Explaination / Solution:
Inverse of any identity matrix is always an identity matrix.
